Agent: Yaya Toure will quit City when Pep Guardiola arrives

Guardiola and Toure celebrate winning the 2009 Champions League final against Manchester United
Guardiola and Toure celebrate winning the 2009 Champions League final against Manchester United

The agent of Manchester City star Yaya Toure says that the Ivorian will depart the club in the summer due to Pep Guardiola’s appointment.

Guardiola sold Toure to the Citizens two years into his four-season reign at Barcelona for a reported £25million transfer fee.

Following confirmation yesterday that the Spaniard will take the managerial reigns at City once the season finishes, Toure’s agent spoke out regarding the midfielder’s future.

“I think Yaya will leave the club. But before leaving I hope he will win again the League and all the cups,” Toure’s agent Dimitry Seluk told the Sun.

“It’s not a question of whether Pep likes him or not. It’s life, you know.

“Pep can call Yaya and speak to him to let him know ‘I’m with you’ or ‘I am not with you’.”

Seluk accused Guardiola of lacking “balls” to stay on at Barcelona when they failed to win La Liga in 2012.

He said: “In my opinion, everyone who has balls must stay in a team not only when they are successful but when things are difficult.

“Barcelona win because it’s like a big family and their structure is an example for everybody.

“So it’s not a question of persons. Luis Enrique has done the same as Guardiola. It’s not possible to say forever it’s the team of Guardiola.”

Seluk began the exit negotiations by lashing out at City technical director Txiki Begiristain and chief executive Ferran Soriano, two former Barcelona board members who both took up posts with the Sky Blues following Toure’s departure to England.

He added: “Yaya opened the door for the people who worked for Barcelona. Yaya went to a place where many changes were necessary. He was not afraid. But now everybody from Barca comes to City.

“Yaya won every trophy in England without Guardiola. Will Guardiola win without Yaya?”

Guardiola's record, however, speaks for itself: